Let
be an endomorphism of the vector space V.
.
This system of equations has a non trivial solution if, and only if, its determinant is equal to 0.
.
The endomorphism
has two eigenvalues: 5 and -5.
Let's look for eigenvectors. We replace
successively by 5 and by -5 in the last system and
solve for (x,y). We have:
,
with
Properties:
The case of a finite dimensional vector space:
V is now an n-dimensional vector space and a basis for V is given. To every endomorphism
we associate
a square matrix
of order n. The eigenvalues of
are the roots of the characteristic polynomial of
;
they will be called the eigenvalues of the matrix
.
By the same way the eigenvectors of
will
ce also called the eigenvectors of
.
Note that the previous results are independent of the choice of the basis (v.i. 5.2).