Example 5.5.2
Let
(i.e.
is the centrer whose center is the origin and whose radius is equal to 2. Then:
Recall that the point 1 is a point interior to
.
Example 5.5.3
Let
. we wish to compute the following integral:
The two points
and
are interior to
. We decompose the given fraction into simple fractions, by the same method used in Calculus; we have:
hence:
By additivity of the integral, we have: